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40544105131 = 304113332491
BaseRepresentation
bin100101110000100111…
…011111001010101011
310212122120212221102101
4211300213133022223
51131013242331011
630343052514231
72633502131065
oct456047371253
9125576787371
1040544105131
11162160aa302
127a3617b977
133a91a0a86a
141d68964735
1510c46632c1
hex9709df2ab

40544105131 has 4 divisors (see below), whose sum is σ = 40557440664. Its totient is φ = 40530769600.

The previous prime is 40544105089. The next prime is 40544105153. The reversal of 40544105131 is 13150144504.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 40544105131 - 215 = 40544072363 is a prime.

It is a super-2 number, since 2×405441051312 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 40544105131.

It is not an unprimeable number, because it can be changed into a prime (40544109131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6663205 + ... + 6669286.

It is an arithmetic number, because the mean of its divisors is an integer number (10139360166).

Almost surely, 240544105131 is an apocalyptic number.

40544105131 is a deficient number, since it is larger than the sum of its proper divisors (13335533).

40544105131 is a wasteful number, since it uses less digits than its factorization.

40544105131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13335532.

The product of its (nonzero) digits is 4800, while the sum is 28.

Adding to 40544105131 its reverse (13150144504), we get a palindrome (53694249635).

The spelling of 40544105131 in words is "forty billion, five hundred forty-four million, one hundred five thousand, one hundred thirty-one".

Divisors: 1 3041 13332491 40544105131