Base | Representation |
---|---|
bin | 111011000001000011001… |
… | …111010000010110100011 |
3 | 112100201011010222222201021 |
4 | 323001003033100112203 |
5 | 1012421310230400120 |
6 | 12343034554150311 |
7 | 566001661262224 |
oct | 73010317202643 |
9 | 15321133888637 |
10 | 4055577200035 |
11 | 1323a62667649 |
12 | 555bb8722397 |
13 | 23559316bc0a |
14 | 10041066124b |
15 | 707652bdaaa |
hex | 3b0433d05a3 |
4055577200035 has 4 divisors (see below), whose sum is σ = 4866692640048. Its totient is φ = 3244461760024.
The previous prime is 4055577200029. The next prime is 4055577200041. The reversal of 4055577200035 is 5300027755504.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (4055577200029) and next prime (4055577200041).
It is a cyclic number.
It is not a de Polignac number, because 4055577200035 - 27 = 4055577199907 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 4055577199964 and 4055577200000.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 405557719999 + ... + 405557720008.
It is an arithmetic number, because the mean of its divisors is an integer number (1216673160012).
Almost surely, 24055577200035 is an apocalyptic number.
4055577200035 is a deficient number, since it is larger than the sum of its proper divisors (811115440013).
4055577200035 is an equidigital number, since it uses as much as digits as its factorization.
4055577200035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 811115440012.
The product of its (nonzero) digits is 735000, while the sum is 43.
The spelling of 4055577200035 in words is "four trillion, fifty-five billion, five hundred seventy-seven million, two hundred thousand, thirty-five".
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