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4061344222113 = 31353781407371
BaseRepresentation
bin111011000110011010111…
…110101100101110100001
3112101021001001200001202120
4323012122332230232201
51013020113110101423
612345431125334453
7566264616202533
oct73063276545641
915337031601676
104061344222113
111326451a306a2
12557147b67429
13235ca1ba5109
141007da545853
15709a1735ee3
hex3b19afacba1

4061344222113 has 4 divisors (see below), whose sum is σ = 5415125629488. Its totient is φ = 2707562814740.

The previous prime is 4061344222093. The next prime is 4061344222189. The reversal of 4061344222113 is 3112224431604.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4061344222113 - 225 = 4061310667681 is a prime.

It is not an unprimeable number, because it can be changed into a prime (4061345222113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 676890703683 + ... + 676890703688.

It is an arithmetic number, because the mean of its divisors is an integer number (1353781407372).

Almost surely, 24061344222113 is an apocalyptic number.

It is an amenable number.

4061344222113 is a deficient number, since it is larger than the sum of its proper divisors (1353781407375).

4061344222113 is a wasteful number, since it uses less digits than its factorization.

4061344222113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1353781407374.

The product of its (nonzero) digits is 27648, while the sum is 33.

Adding to 4061344222113 its reverse (3112224431604), we get a palindrome (7173568653717).

The spelling of 4061344222113 in words is "four trillion, sixty-one billion, three hundred forty-four million, two hundred twenty-two thousand, one hundred thirteen".

Divisors: 1 3 1353781407371 4061344222113