4067488259313 has 4 divisors (see below), whose sum is σ = 5423317679088. Its totient is φ = 2711658839540.

The previous prime is 4067488259309. The next prime is 4067488259333. The reversal of 4067488259313 is 3139528847604.

4067488259313 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4067488259313 - 2² = 4067488259309 is a prime.

It is not an unprimeable number, because it can be changed into a prime (4067488259333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 677914709883 + ... + 677914709888.

It is an arithmetic number, because the mean of its divisors is an integer number (1355829419772).

It is a 1-persistent number, because it is pandigital, but 2⋅4067488259313 = 8134976518626 is not.

Almost surely, 2^{4067488259313} is an apocalyptic number.

It is an amenable number.

4067488259313 is a deficient number, since it is larger than the sum of its proper divisors (1355829419775).

4067488259313 is a wasteful number, since it uses less digits than its factorization.

4067488259313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1355829419774.

The product of its (nonzero) digits is 34836480, while the sum is 60.

The spelling of 4067488259313 in words is "four trillion, sixty-seven billion, four hundred eighty-eight million, two hundred fifty-nine thousand, three hundred thirteen".