Base | Representation |
---|---|
bin | 10010100011011100101000… |
… | …10101010100011010101011 |
3 | 12100110110220211200012110211 |
4 | 21101232110111110122223 |
5 | 20321433141014230243 |
6 | 222435234232521551 |
7 | 11410505345004046 |
oct | 1121562425243253 |
9 | 170413824605424 |
10 | 40800382961323 |
11 | 12000388577327 |
12 | 46ab4798502b7 |
13 | 199c5c899b16b |
14 | a10a6b64bc5d |
15 | 4ab4a1958d9d |
hex | 251b945546ab |
40800382961323 has 4 divisors (see below), whose sum is σ = 42207292718640. Its totient is φ = 39393473204008.
The previous prime is 40800382961311. The next prime is 40800382961357. The reversal of 40800382961323 is 32316928300804.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 40800382961323 - 213 = 40800382953131 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (40800382901323) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 703454878615 + ... + 703454878672.
It is an arithmetic number, because the mean of its divisors is an integer number (10551823179660).
Almost surely, 240800382961323 is an apocalyptic number.
40800382961323 is a deficient number, since it is larger than the sum of its proper divisors (1406909757317).
40800382961323 is a wasteful number, since it uses less digits than its factorization.
40800382961323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1406909757316.
The product of its (nonzero) digits is 1492992, while the sum is 49.
The spelling of 40800382961323 in words is "forty trillion, eight hundred billion, three hundred eighty-two million, nine hundred sixty-one thousand, three hundred twenty-three".
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