Base | Representation |
---|---|
bin | 10010100111110110001000… |
… | …11001000111110001000011 |
3 | 12100222221000100201201100011 |
4 | 21103323010121013301003 |
5 | 20331422144324313221 |
6 | 223032510532405351 |
7 | 11424435446110030 |
oct | 1123730431076103 |
9 | 170887010651304 |
10 | 40951513119811 |
11 | 12059491609258 |
12 | 4714816a76857 |
13 | 19b093242a448 |
14 | a180c714c387 |
15 | 4b039987a1e1 |
hex | 253ec4647c43 |
40951513119811 has 4 divisors (see below), whose sum is σ = 46801729279792. Its totient is φ = 35101296959832.
The previous prime is 40951513119793. The next prime is 40951513119823. The reversal of 40951513119811 is 11891131515904.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 40951513119811 - 25 = 40951513119779 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (40951513119211) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2925108079980 + ... + 2925108079993.
It is an arithmetic number, because the mean of its divisors is an integer number (11700432319948).
Almost surely, 240951513119811 is an apocalyptic number.
40951513119811 is a deficient number, since it is larger than the sum of its proper divisors (5850216159981).
40951513119811 is an equidigital number, since it uses as much as digits as its factorization.
40951513119811 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5850216159980.
The product of its (nonzero) digits is 194400, while the sum is 49.
The spelling of 40951513119811 in words is "forty trillion, nine hundred fifty-one billion, five hundred thirteen million, one hundred nineteen thousand, eight hundred eleven".
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