4110123000131 has 16 divisors (see below), whose sum is σ = 4220412260064. Its totient is φ = 4000509886464.

The previous prime is 4110123000119. The next prime is 4110123000143. The reversal of 4110123000131 is 1310003210114.

It is an interprime number because it is at equal distance from previous prime (4110123000119) and next prime (4110123000143).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4110123000131 is a prime.

It is a super-2 number, since 2×4110123000131² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4110123000631) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 46483595 + ... + 46571931.

It is an arithmetic number, because the mean of its divisors is an integer number (263775766254).

Almost surely, 2^{4110123000131} is an apocalyptic number.

4110123000131 is a deficient number, since it is larger than the sum of its proper divisors (110289259933).

4110123000131 is a wasteful number, since it uses less digits than its factorization.

4110123000131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 92150.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 4110123000131 its reverse (1310003210114), we get a palindrome (5420126210245).

It can be divided in two parts, 411012 and 3000131, that added together give a palindrome (3411143).

The spelling of 4110123000131 in words is "four trillion, one hundred ten billion, one hundred twenty-three million, one hundred thirty-one", and thus it is an aban number.