Base | Representation |
---|---|
bin | 101110101110101110100011… |
… | …0110000000100001001100001 |
3 | 1222220101021101112021121011022 |
4 | 1131131131012300010021201 |
5 | 412334004410141242423 |
6 | 4014114142512455225 |
7 | 152402556620250206 |
oct | 13535350660041141 |
9 | 1886337345247138 |
10 | 411042442134113 |
11 | 109a751368040a9 |
12 | 3a12694224a515 |
13 | 1484819c97301a |
14 | 73707bb857cad |
15 | 327c2558b9dc8 |
hex | 175d746c04261 |
411042442134113 has 16 divisors (see below), whose sum is σ = 419208304499712. Its totient is φ = 402943380840000.
The previous prime is 411042442134097. The next prime is 411042442134131. The reversal of 411042442134113 is 311431244240114.
It is a cyclic number.
It is not a de Polignac number, because 411042442134113 - 24 = 411042442134097 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (411042442137113) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 70458320 + ... + 76068782.
It is an arithmetic number, because the mean of its divisors is an integer number (26200519031232).
Almost surely, 2411042442134113 is an apocalyptic number.
It is an amenable number.
411042442134113 is a deficient number, since it is larger than the sum of its proper divisors (8165862365599).
411042442134113 is a wasteful number, since it uses less digits than its factorization.
411042442134113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5616416.
The product of its (nonzero) digits is 36864, while the sum is 35.
Adding to 411042442134113 its reverse (311431244240114), we get a palindrome (722473686374227).
The spelling of 411042442134113 in words is "four hundred eleven trillion, forty-two billion, four hundred forty-two million, one hundred thirty-four thousand, one hundred thirteen".
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