Base | Representation |
---|---|
bin | 10010101100011111001101… |
… | …00011010101000101101001 |
3 | 12101120011200021110020112020 |
4 | 21112033212203111011221 |
5 | 20342030312000323423 |
6 | 223234044354135053 |
7 | 11442112622241354 |
oct | 1126174643250551 |
9 | 171504607406466 |
10 | 41111000011113 |
11 | 1211009382123a |
12 | 473b706881489 |
13 | 19c299b2a2446 |
14 | a21ad685729b |
15 | 4b45d12604e3 |
hex | 2563e68d5169 |
41111000011113 has 8 divisors (see below), whose sum is σ = 54815402677728. Its totient is φ = 27406965342624.
The previous prime is 41111000011099. The next prime is 41111000011157. The reversal of 41111000011113 is 31111000011114.
41111000011113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 41111000011113 - 212 = 41111000007017 is a prime.
It is a super-2 number, since 2×411110000111132 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 41111000011092 and 41111000011101.
It is not an unprimeable number, because it can be changed into a prime (41111000011163) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 91738756 + ... + 92185797.
It is an arithmetic number, because the mean of its divisors is an integer number (6851925334716).
Almost surely, 241111000011113 is an apocalyptic number.
It is an amenable number.
41111000011113 is a deficient number, since it is larger than the sum of its proper divisors (13704402666615).
41111000011113 is a wasteful number, since it uses less digits than its factorization.
41111000011113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 183999063.
The product of its (nonzero) digits is 12, while the sum is 15.
Adding to 41111000011113 its reverse (31111000011114), we get a palindrome (72222000022227).
Subtracting from 41111000011113 its reverse (31111000011114), we obtain a palindrome (9999999999999).
The spelling of 41111000011113 in words is "forty-one trillion, one hundred eleven billion, eleven thousand, one hundred thirteen".
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