41111114022131 has 4 divisors (see below), whose sum is σ = 41115667261200. Its totient is φ = 41106560783064.

The previous prime is 41111114022037. The next prime is 41111114022163. The reversal of 41111114022131 is 13122041111114.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 41111114022131 - 2¹⁴ = 41111114005747 is a prime.

It is a super-2 number, since 2×41111114022131² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 41111114022097 and 41111114022106.

It is not an unprimeable number, because it can be changed into a prime (41111114024131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2276605991 + ... + 2276624048.

It is an arithmetic number, because the mean of its divisors is an integer number (10278916815300).

Almost surely, 2^{41111114022131} is an apocalyptic number.

41111114022131 is a deficient number, since it is larger than the sum of its proper divisors (4553239069).

41111114022131 is an equidigital number, since it uses as much as digits as its factorization.

41111114022131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4553239068.

The product of its (nonzero) digits is 192, while the sum is 23.

Adding to 41111114022131 its reverse (13122041111114), we get a palindrome (54233155133245).

The spelling of 41111114022131 in words is "forty-one trillion, one hundred eleven billion, one hundred fourteen million, twenty-two thousand, one hundred thirty-one".