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4111314131 = 7735318647
BaseRepresentation
bin1111010100001101…
…1010110011010011
3101121112011101201202
43311003122303103
531404444023011
61515543421415
7203611410401
oct36503326323
911545141652
104111314131
11181a803181
12968a5486b
135069c6c72
142b004c471
15190e1223b
hexf50dacd3

4111314131 has 4 divisors (see below), whose sum is σ = 4116633552. Its totient is φ = 4105994712.

The previous prime is 4111314121. The next prime is 4111314161. The reversal of 4111314131 is 1314131114.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4111314131 - 214 = 4111297747 is a prime.

It is a super-2 number, since 2×41113141312 = 33805807767520570322, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4111314121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2658551 + ... + 2660096.

It is an arithmetic number, because the mean of its divisors is an integer number (1029158388).

Almost surely, 24111314131 is an apocalyptic number.

4111314131 is a deficient number, since it is larger than the sum of its proper divisors (5319421).

4111314131 is an equidigital number, since it uses as much as digits as its factorization.

4111314131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5319420.

The product of its digits is 144, while the sum is 20.

The square root of 4111314131 is about 64119.5300279096. The cubic root of 4111314131 is about 1601.9915475320.

Adding to 4111314131 its reverse (1314131114), we get a palindrome (5425445245).

The spelling of 4111314131 in words is "four billion, one hundred eleven million, three hundred fourteen thousand, one hundred thirty-one".

Divisors: 1 773 5318647 4111314131