4111413001 has 4 divisors (see below), whose sum is σ = 4290170112. Its totient is φ = 3932655892.

The previous prime is 4111412951. The next prime is 4111413011. The reversal of 4111413001 is 1003141114.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4111413001 - 2¹⁵ = 4111380233 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4111413011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 89378521 + ... + 89378566.

It is an arithmetic number, because the mean of its divisors is an integer number (1072542528).

Almost surely, 2^4111413001 is an apocalyptic number.

It is an amenable number.

4111413001 is a deficient number, since it is larger than the sum of its proper divisors (178757111).

4111413001 is a wasteful number, since it uses less digits than its factorization.

4111413001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 178757110.

The product of its (nonzero) digits is 48, while the sum is 16.

The square root of 4111413001 is about 64120.3010052199. The cubic root of 4111413001 is about 1602.0043891384.

Adding to 4111413001 its reverse (1003141114), we get a palindrome (5114554115).

The spelling of 4111413001 in words is "four billion, one hundred eleven million, four hundred thirteen thousand, one".