Base | Representation |
---|---|
bin | 1011111101110100001… |
… | …11011110000011111001 |
3 | 1110022020100202020012220 |
4 | 11332322013132003321 |
5 | 23214010432212213 |
6 | 512513243354253 |
7 | 41463353565165 |
oct | 5767207360371 |
9 | 1408210666186 |
10 | 411144413433 |
11 | 149402337136 |
12 | 67823522989 |
13 | 2ca03459b10 |
14 | 15c84305ca5 |
15 | aa64eb1e23 |
hex | 5fba1de0f9 |
411144413433 has 16 divisors (see below), whose sum is σ = 590480343936. Its totient is φ = 252960888960.
The previous prime is 411144413423. The next prime is 411144413437. The reversal of 411144413433 is 334314441114.
It is not a de Polignac number, because 411144413433 - 214 = 411144397049 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 411144413394 and 411144413403.
It is not an unprimeable number, because it can be changed into a prime (411144413437) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 867508 + ... + 1254933.
It is an arithmetic number, because the mean of its divisors is an integer number (36905021496).
Almost surely, 2411144413433 is an apocalyptic number.
It is an amenable number.
411144413433 is a deficient number, since it is larger than the sum of its proper divisors (179335930503).
411144413433 is a wasteful number, since it uses less digits than its factorization.
411144413433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2127424.
The product of its digits is 27648, while the sum is 33.
Adding to 411144413433 its reverse (334314441114), we get a palindrome (745458854547).
The spelling of 411144413433 in words is "four hundred eleven billion, one hundred forty-four million, four hundred thirteen thousand, four hundred thirty-three".
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