411153415023041 has 4 divisors (see below), whose sum is σ = 411208316007300. Its totient is φ = 411098514038784.

The previous prime is 411153415022941. The next prime is 411153415023067. The reversal of 411153415023041 is 140320514351114.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 311358729529600 + 99794685493441 = 17645360^2 + 9989729^2 .

It is a cyclic number.

It is not a de Polignac number, because 411153415023041 - 2¹⁸ = 411153414760897 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 411153415022992 and 411153415023010.

It is not an unprimeable number, because it can be changed into a prime (411153405023041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27450480896 + ... + 27450495873.

It is an arithmetic number, because the mean of its divisors is an integer number (102802079001825).

Almost surely, 2^{411153415023041} is an apocalyptic number.

It is an amenable number.

411153415023041 is a deficient number, since it is larger than the sum of its proper divisors (54900984259).

411153415023041 is an equidigital number, since it uses as much as digits as its factorization.

411153415023041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 54900984258.

The product of its (nonzero) digits is 28800, while the sum is 35.

Adding to 411153415023041 its reverse (140320514351114), we get a palindrome (551473929374155).

The spelling of 411153415023041 in words is "four hundred eleven trillion, one hundred fifty-three billion, four hundred fifteen million, twenty-three thousand, forty-one".