4112024000113 has 4 divisors (see below), whose sum is σ = 4173397492720. Its totient is φ = 4050650507508.

The previous prime is 4112024000111. The next prime is 4112024000153. The reversal of 4112024000113 is 3110004202114.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4112024000113 - 2¹ = 4112024000111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4112024000111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30686746203 + ... + 30686746336.

It is an arithmetic number, because the mean of its divisors is an integer number (1043349373180).

Almost surely, 2^{4112024000113} is an apocalyptic number.

It is an amenable number.

4112024000113 is a deficient number, since it is larger than the sum of its proper divisors (61373492607).

4112024000113 is an equidigital number, since it uses as much as digits as its factorization.

4112024000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 61373492606.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 4112024000113 its reverse (3110004202114), we get a palindrome (7222028202227).

The spelling of 4112024000113 in words is "four trillion, one hundred twelve billion, twenty-four million, one hundred thirteen", and thus it is an aban number.