Base | Representation |
---|---|
bin | 111011110101101100011… |
… | …001001011110001000011 |
3 | 112120010001110211201002201 |
4 | 323311230121023301003 |
5 | 1014333041133242040 |
6 | 12425023530054031 |
7 | 603042504233056 |
oct | 73655431136103 |
9 | 15503043751081 |
10 | 4112102243395 |
11 | 1345a29572313 |
12 | 564b5287a317 |
13 | 23aa009ba633 |
14 | 1030537d4a9d |
15 | 71e7290ea9a |
hex | 3bd6c64bc43 |
4112102243395 has 16 divisors (see below), whose sum is σ = 4979908501920. Its totient is φ = 3259425982464.
The previous prime is 4112102243351. The next prime is 4112102243399. The reversal of 4112102243395 is 5933422012114.
It is a cyclic number.
It is not a de Polignac number, because 4112102243395 - 29 = 4112102242883 is a prime.
It is a super-2 number, since 2×41121022433952 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (4112102243399) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 43990947 + ... + 44084323.
It is an arithmetic number, because the mean of its divisors is an integer number (311244281370).
Almost surely, 24112102243395 is an apocalyptic number.
4112102243395 is a deficient number, since it is larger than the sum of its proper divisors (867806258525).
4112102243395 is a wasteful number, since it uses less digits than its factorization.
4112102243395 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 174294.
The product of its (nonzero) digits is 51840, while the sum is 37.
The spelling of 4112102243395 in words is "four trillion, one hundred twelve billion, one hundred two million, two hundred forty-three thousand, three hundred ninety-five".
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