41123010113 has 4 divisors (see below), whose sum is σ = 41223555780. Its totient is φ = 41022464448.

The previous prime is 41123010073. The next prime is 41123010119. The reversal of 41123010113 is 31101032114.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 23394620209 + 17728389904 = 152953^2 + 133148^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-41123010113 is a prime.

It is a super-2 number, since 2×41123010113² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 41123010091 and 41123010100.

It is not an unprimeable number, because it can be changed into a prime (41123010119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50272220 + ... + 50273037.

It is an arithmetic number, because the mean of its divisors is an integer number (10305888945).

Almost surely, 2^41123010113 is an apocalyptic number.

It is an amenable number.

41123010113 is a deficient number, since it is larger than the sum of its proper divisors (100545667).

41123010113 is a wasteful number, since it uses less digits than its factorization.

41123010113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 100545666.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 41123010113 its reverse (31101032114), we get a palindrome (72224042227).

The spelling of 41123010113 in words is "forty-one billion, one hundred twenty-three million, ten thousand, one hundred thirteen".