Base | Representation |
---|---|
bin | 111011110110000111001… |
… | …001100011001111101011 |
3 | 112120011012202111111212220 |
4 | 323312013021203033223 |
5 | 1014340001042130331 |
6 | 12425140243205123 |
7 | 603056564554455 |
oct | 73660711431753 |
9 | 15504182444786 |
10 | 4112551130091 |
11 | 1346139998558 |
12 | 5650590767a3 |
13 | 23aa729b7671 |
14 | 1030972832d5 |
15 | 71e9c02d296 |
hex | 3bd872633eb |
4112551130091 has 16 divisors (see below), whose sum is σ = 5632813091328. Its totient is φ = 2667026844000.
The previous prime is 4112551130089. The next prime is 4112551130099. The reversal of 4112551130091 is 1900311552114.
It is not a de Polignac number, because 4112551130091 - 21 = 4112551130089 is a prime.
It is a super-2 number, since 2×41125511300912 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (4112551130099) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3466755 + ... + 4499276.
It is an arithmetic number, because the mean of its divisors is an integer number (352050818208).
Almost surely, 24112551130091 is an apocalyptic number.
4112551130091 is a deficient number, since it is larger than the sum of its proper divisors (1520261961237).
4112551130091 is a wasteful number, since it uses less digits than its factorization.
4112551130091 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7970722.
The product of its (nonzero) digits is 5400, while the sum is 33.
The spelling of 4112551130091 in words is "four trillion, one hundred twelve billion, five hundred fifty-one million, one hundred thirty thousand, ninety-one".
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