Base | Representation |
---|---|
bin | 100110010011010001… |
… | …011010011010001011 |
3 | 10221011002220221002202 |
4 | 212103101122122023 |
5 | 1133211113133120 |
6 | 30520502350415 |
7 | 2654062106144 |
oct | 462321323213 |
9 | 127132827082 |
10 | 41125521035 |
11 | 16494314715 |
12 | 7b78a2b40b |
13 | 3b552ca641 |
14 | 1dc1c70acb |
15 | 110a70e875 |
hex | 99345a68b |
41125521035 has 16 divisors (see below), whose sum is σ = 51358104000. Its totient is φ = 31575686016.
The previous prime is 41125520987. The next prime is 41125521037. The reversal of 41125521035 is 53012552114.
It is a cyclic number.
It is not a de Polignac number, because 41125521035 - 216 = 41125455499 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (29).
It is a junction number, because it is equal to n+sod(n) for n = 41125520989 and 41125521007.
It is not an unprimeable number, because it can be changed into a prime (41125521037) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 824960 + ... + 873389.
It is an arithmetic number, because the mean of its divisors is an integer number (3209881500).
Almost surely, 241125521035 is an apocalyptic number.
41125521035 is a deficient number, since it is larger than the sum of its proper divisors (10232582965).
41125521035 is a wasteful number, since it uses less digits than its factorization.
41125521035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1698550.
The product of its (nonzero) digits is 6000, while the sum is 29.
The spelling of 41125521035 in words is "forty-one billion, one hundred twenty-five million, five hundred twenty-one thousand, thirty-five".
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