411300142412033 has 16 divisors (see below), whose sum is σ = 470499180875136. Its totient is φ = 352211665603200.

The previous prime is 411300142412009. The next prime is 411300142412119. The reversal of 411300142412033 is 330214241003114.

It is a cyclic number.

It is not a de Polignac number, because 411300142412033 - 2⁶ = 411300142411969 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 411300142411987 and 411300142412005.

It is not an unprimeable number, because it can be changed into a prime (411300142415033) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 49347485 + ... + 57076917.

It is an arithmetic number, because the mean of its divisors is an integer number (29406198804696).

Almost surely, 2^{411300142412033} is an apocalyptic number.

It is an amenable number.

411300142412033 is a deficient number, since it is larger than the sum of its proper divisors (59199038463103).

411300142412033 is a wasteful number, since it uses less digits than its factorization.

411300142412033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7736584.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 411300142412033 its reverse (330214241003114), we get a palindrome (741514383415147).

The spelling of 411300142412033 in words is "four hundred eleven trillion, three hundred billion, one hundred forty-two million, four hundred twelve thousand, thirty-three".