41130025664513 has 4 divisors (see below), whose sum is σ = 41138273118000. Its totient is φ = 41121778211028.

The previous prime is 41130025664437. The next prime is 41130025664527. The reversal of 41130025664513 is 31546652003114.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 41130025664513 - 2²⁶ = 41129958555649 is a prime.

It is a super-4 number, since 4×41130025664513⁴ (a number of 56 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (41130025664713) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4123719263 + ... + 4123729236.

It is an arithmetic number, because the mean of its divisors is an integer number (10284568279500).

Almost surely, 2^{41130025664513} is an apocalyptic number.

It is an amenable number.

41130025664513 is a deficient number, since it is larger than the sum of its proper divisors (8247453487).

41130025664513 is an equidigital number, since it uses as much as digits as its factorization.

41130025664513 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8247453486.

The product of its (nonzero) digits is 259200, while the sum is 41.

Adding to 41130025664513 its reverse (31546652003114), we get a palindrome (72676677667627).

The spelling of 41130025664513 in words is "forty-one trillion, one hundred thirty billion, twenty-five million, six hundred sixty-four thousand, five hundred thirteen".