4113015340411 has 4 divisors (see below), whose sum is σ = 4113020330712. Its totient is φ = 4113010350112.

The previous prime is 4113015340391. The next prime is 4113015340429. The reversal of 4113015340411 is 1140435103114.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 4113015340411 - 2⁹ = 4113015339899 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 4113015340411.

It is not an unprimeable number, because it can be changed into a prime (4113015340111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 932725 + ... + 3015958.

It is an arithmetic number, because the mean of its divisors is an integer number (1028255082678).

Almost surely, 2^{4113015340411} is an apocalyptic number.

4113015340411 is a deficient number, since it is larger than the sum of its proper divisors (4990301).

4113015340411 is a wasteful number, since it uses less digits than its factorization.

4113015340411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4990300.

The product of its (nonzero) digits is 2880, while the sum is 28.

The spelling of 4113015340411 in words is "four trillion, one hundred thirteen billion, fifteen million, three hundred forty thousand, four hundred eleven".