Base | Representation |
---|---|
bin | 111011110110100011010… |
… | …011001111100111110011 |
3 | 112120012102200012222221202 |
4 | 323312203103033213303 |
5 | 1014341432444330303 |
6 | 12425255154241415 |
7 | 603104361224456 |
oct | 73664323174763 |
9 | 15505380188852 |
10 | 4113023433203 |
11 | 1346361557903 |
12 | 56516b28626b |
13 | 23ab197c2b69 |
14 | 1030ddca949d |
15 | 71ec8724c88 |
hex | 3bda34cf9f3 |
4113023433203 has 4 divisors (see below), whose sum is σ = 4329498350760. Its totient is φ = 3896548515648.
The previous prime is 4113023433191. The next prime is 4113023433209. The reversal of 4113023433203 is 3023343203114.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4113023433203 - 230 = 4111949691379 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4113023433209) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 108237458750 + ... + 108237458787.
It is an arithmetic number, because the mean of its divisors is an integer number (1082374587690).
Almost surely, 24113023433203 is an apocalyptic number.
4113023433203 is a deficient number, since it is larger than the sum of its proper divisors (216474917557).
4113023433203 is a wasteful number, since it uses less digits than its factorization.
4113023433203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 216474917556.
The product of its (nonzero) digits is 15552, while the sum is 29.
Adding to 4113023433203 its reverse (3023343203114), we get a palindrome (7136366636317).
The spelling of 4113023433203 in words is "four trillion, one hundred thirteen billion, twenty-three million, four hundred thirty-three thousand, two hundred three".
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