4113033144041 has 4 divisors (see below), whose sum is σ = 4113743395584. Its totient is φ = 4112322892500.

The previous prime is 4113033144037. The next prime is 4113033144097. The reversal of 4113033144041 is 1404413303114.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4113033144041 - 2² = 4113033144037 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4113033143995 and 4113033144013.

It is not an unprimeable number, because it can be changed into a prime (4113033114041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 355117085 + ... + 355128666.

It is an arithmetic number, because the mean of its divisors is an integer number (1028435848896).

Almost surely, 2^{4113033144041} is an apocalyptic number.

It is an amenable number.

4113033144041 is a deficient number, since it is larger than the sum of its proper divisors (710251543).

4113033144041 is an equidigital number, since it uses as much as digits as its factorization.

4113033144041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 710251542.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 4113033144041 its reverse (1404413303114), we get a palindrome (5517446447155).

The spelling of 4113033144041 in words is "four trillion, one hundred thirteen billion, thirty-three million, one hundred forty-four thousand, forty-one".