411313424313115 has 4 divisors (see below), whose sum is σ = 493576109175744. Its totient is φ = 329050739450488.

The previous prime is 411313424313083. The next prime is 411313424313151. The reversal of 411313424313115 is 511313424313114.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 411313424313115 - 2⁵ = 411313424313083 is a prime.

It is a super-2 number, since 2×411313424313115² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41131342431307 + ... + 41131342431316.

It is an arithmetic number, because the mean of its divisors is an integer number (123394027293936).

Almost surely, 2^{411313424313115} is an apocalyptic number.

411313424313115 is a deficient number, since it is larger than the sum of its proper divisors (82262684862629).

411313424313115 is an equidigital number, since it uses as much as digits as its factorization.

411313424313115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 82262684862628.

The product of its digits is 51840, while the sum is 37.

Adding to 411313424313115 its reverse (511313424313114), we get a palindrome (922626848626229).

Subtracting 411313424313115 from its reverse (511313424313114), we obtain a palindrome (99999999999999).

The spelling of 411313424313115 in words is "four hundred eleven trillion, three hundred thirteen billion, four hundred twenty-four million, three hundred thirteen thousand, one hundred fifteen".