Base | Representation |
---|---|
bin | 111011110110101111110… |
… | …111010000010111000011 |
3 | 112120012222100211001122112 |
4 | 323312233313100113003 |
5 | 1014342400423400003 |
6 | 12425332123525535 |
7 | 603112530554105 |
oct | 73665767202703 |
9 | 15505870731575 |
10 | 4113234200003 |
11 | 134645a524045 |
12 | 5652099898ab |
13 | 23ab51379a46 |
14 | 10311dc91575 |
15 | 71edbea93d8 |
hex | 3bdafdd05c3 |
4113234200003 has 4 divisors (see below), whose sum is σ = 4118667799440. Its totient is φ = 4107800600568.
The previous prime is 4113234199973. The next prime is 4113234200011. The reversal of 4113234200003 is 3000024323114.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4113234200003 - 216 = 4113234134467 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4113234200083) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2716798583 + ... + 2716800096.
It is an arithmetic number, because the mean of its divisors is an integer number (1029666949860).
Almost surely, 24113234200003 is an apocalyptic number.
4113234200003 is a deficient number, since it is larger than the sum of its proper divisors (5433599437).
4113234200003 is an equidigital number, since it uses as much as digits as its factorization.
4113234200003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5433599436.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 4113234200003 its reverse (3000024323114), we get a palindrome (7113258523117).
The spelling of 4113234200003 in words is "four trillion, one hundred thirteen billion, two hundred thirty-four million, two hundred thousand, three".
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