Base | Representation |
---|---|
bin | 10010101101000110111101… |
… | …10001011010110000101011 |
3 | 12101122012202210112122011101 |
4 | 21112203132301122300223 |
5 | 20342403020121314430 |
6 | 223251534344542231 |
7 | 11443466560013263 |
oct | 1126433661326053 |
9 | 171565683478141 |
10 | 41132344323115 |
11 | 12119147063811 |
12 | 4743882a81977 |
13 | 19c49c032b466 |
14 | a22b5d4b67a3 |
15 | 4b4e30020dca |
hex | 2568dec5ac2b |
41132344323115 has 4 divisors (see below), whose sum is σ = 49358813187744. Its totient is φ = 32905875458488.
The previous prime is 41132344323067. The next prime is 41132344323197. The reversal of 41132344323115 is 51132344323114.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 41132344323115 - 215 = 41132344290347 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4113234432307 + ... + 4113234432316.
It is an arithmetic number, because the mean of its divisors is an integer number (12339703296936).
Almost surely, 241132344323115 is an apocalyptic number.
41132344323115 is a deficient number, since it is larger than the sum of its proper divisors (8226468864629).
41132344323115 is an equidigital number, since it uses as much as digits as its factorization.
41132344323115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8226468864628.
The product of its digits is 103680, while the sum is 37.
Adding to 41132344323115 its reverse (51132344323114), we get a palindrome (92264688646229).
Subtracting 41132344323115 from its reverse (51132344323114), we obtain a palindrome (9999999999999).
The spelling of 41132344323115 in words is "forty-one trillion, one hundred thirty-two billion, three hundred forty-four million, three hundred twenty-three thousand, one hundred fifteen".
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