4113343140113 has 4 divisors (see below), whose sum is σ = 4115181918900. Its totient is φ = 4111504361328.

The previous prime is 4113343140083. The next prime is 4113343140143. The reversal of 4113343140113 is 3110413433114.

4113343140113 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (4113343140083) and next prime (4113343140143).

It can be written as a sum of positive squares in 2 ways, for example, as 1628091785089 + 2485251355024 = 1275967^2 + 1576468^2 .

It is a cyclic number.

It is not a de Polignac number, because 4113343140113 - 2¹² = 4113343136017 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4113343140143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 919386038 + ... + 919390511.

It is an arithmetic number, because the mean of its divisors is an integer number (1028795479725).

Almost surely, 2^{4113343140113} is an apocalyptic number.

It is an amenable number.

4113343140113 is a deficient number, since it is larger than the sum of its proper divisors (1838778787).

4113343140113 is a wasteful number, since it uses less digits than its factorization.

4113343140113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1838778786.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 4113343140113 its reverse (3110413433114), we get a palindrome (7223756573227).

The spelling of 4113343140113 in words is "four trillion, one hundred thirteen billion, three hundred forty-three million, one hundred forty thousand, one hundred thirteen".