Base | Representation |
---|---|
bin | 10010101101001010000110… |
… | …10000111111111000000011 |
3 | 12101122101010022001022111002 |
4 | 21112211003100333320003 |
5 | 20342414443230320303 |
6 | 223252413533442215 |
7 | 11443556421536366 |
oct | 1126450320777003 |
9 | 171571108038432 |
10 | 41134030323203 |
11 | 12119931834614 |
12 | 474407364036b |
13 | 19c4bcb71564c |
14 | a22c7d3960dd |
15 | 4b4ecd05b788 |
hex | 25694343fe03 |
41134030323203 has 4 divisors (see below), whose sum is σ = 41533389841008. Its totient is φ = 40734670805400.
The previous prime is 41134030323187. The next prime is 41134030323233. The reversal of 41134030323203 is 30232303043114.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 41134030323203 - 24 = 41134030323187 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (41134030323233) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 199679758748 + ... + 199679758953.
It is an arithmetic number, because the mean of its divisors is an integer number (10383347460252).
Almost surely, 241134030323203 is an apocalyptic number.
41134030323203 is a deficient number, since it is larger than the sum of its proper divisors (399359517805).
41134030323203 is a wasteful number, since it uses less digits than its factorization.
41134030323203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 399359517804.
The product of its (nonzero) digits is 15552, while the sum is 29.
Adding to 41134030323203 its reverse (30232303043114), we get a palindrome (71366333366317).
The spelling of 41134030323203 in words is "forty-one trillion, one hundred thirty-four billion, thirty million, three hundred twenty-three thousand, two hundred three".
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