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41134131323 = 377315229223
BaseRepresentation
bin100110010011110010…
…010000100001111011
310221011201010101012022
4212103302100201323
51133220314200243
630521411105055
72654225230055
oct462362204173
9127151111168
1041134131323
111649916575a
127b7b8a218b
133b5702379c
141dc30728d5
15110b360b68
hex993c9087b

41134131323 has 8 divisors (see below), whose sum is σ = 42824577888. Its totient is φ = 39474143424.

The previous prime is 41134131319. The next prime is 41134131331. The reversal of 41134131323 is 32313143114.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 41134131323 - 22 = 41134131319 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 41134131292 and 41134131301.

It is not an unprimeable number, because it can be changed into a prime (41134131343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7611911 + ... + 7617312.

It is an arithmetic number, because the mean of its divisors is an integer number (5353072236).

Almost surely, 241134131323 is an apocalyptic number.

41134131323 is a deficient number, since it is larger than the sum of its proper divisors (1690446565).

41134131323 is a wasteful number, since it uses less digits than its factorization.

41134131323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15229333.

The product of its digits is 2592, while the sum is 26.

Adding to 41134131323 its reverse (32313143114), we get a palindrome (73447274437).

The spelling of 41134131323 in words is "forty-one billion, one hundred thirty-four million, one hundred thirty-one thousand, three hundred twenty-three".

Divisors: 1 37 73 2701 15229223 563481251 1111733279 41134131323