41135005010033 has 8 divisors (see below), whose sum is σ = 44942439809856. Its totient is φ = 37338885025200.

The previous prime is 41135005009981. The next prime is 41135005010039. The reversal of 41135005010033 is 33001050053114.

41135005010033 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 41135005010033 - 2¹⁰ = 41135005009009 is a prime.

It is a super-2 number, since 2×41135005010033² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 41135005009984 and 41135005010011.

It is not an unprimeable number, because it can be changed into a prime (41135005010039) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2828696141 + ... + 2828710682.

It is an arithmetic number, because the mean of its divisors is an integer number (5617804976232).

Almost surely, 2^{41135005010033} is an apocalyptic number.

It is an amenable number.

41135005010033 is a deficient number, since it is larger than the sum of its proper divisors (3807434799823).

41135005010033 is a wasteful number, since it uses less digits than its factorization.

41135005010033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5657407495.

The product of its (nonzero) digits is 2700, while the sum is 26.

Adding to 41135005010033 its reverse (33001050053114), we get a palindrome (74136055063147).

The spelling of 41135005010033 in words is "forty-one trillion, one hundred thirty-five billion, five million, ten thousand, thirty-three".