411353302013041 has 4 divisors (see below), whose sum is σ = 411353389161712. Its totient is φ = 411353214864372.

The previous prime is 411353302013039. The next prime is 411353302013051. The reversal of 411353302013041 is 140310203353114.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 411353302013041 - 2¹ = 411353302013039 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 411353302012994 and 411353302013012.

It is not an unprimeable number, because it can be changed into a prime (411353302013051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36062475 + ... + 46078288.

It is an arithmetic number, because the mean of its divisors is an integer number (102838347290428).

Almost surely, 2^{411353302013041} is an apocalyptic number.

It is an amenable number.

411353302013041 is a deficient number, since it is larger than the sum of its proper divisors (87148671).

411353302013041 is an equidigital number, since it uses as much as digits as its factorization.

411353302013041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 87148670.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 411353302013041 its reverse (140310203353114), we get a palindrome (551663505366155).

The spelling of 411353302013041 in words is "four hundred eleven trillion, three hundred fifty-three billion, three hundred two million, thirteen thousand, forty-one".