Base | Representation |
---|---|
bin | 101110110001000000010110… |
… | …0110110001000111010111001 |
3 | 1222221111012112212101211112020 |
4 | 1131202000230312020322321 |
5 | 412404122121233202023 |
6 | 4014514043141305053 |
7 | 152434312521312105 |
oct | 13542005466107271 |
9 | 1887435485354466 |
10 | 411355540131513 |
11 | 10a0859a542973a |
12 | 3a177562105189 |
13 | 1486b879265743 |
14 | 7381a00354905 |
15 | 328547cdd6de3 |
hex | 176202cd88eb9 |
411355540131513 has 16 divisors (see below), whose sum is σ = 549748428182016. Its totient is φ = 273599857140480.
The previous prime is 411355540131491. The next prime is 411355540131559. The reversal of 411355540131513 is 315131045553114.
It is not a de Polignac number, because 411355540131513 - 213 = 411355540123321 is a prime.
It is not an unprimeable number, because it can be changed into a prime (411355540131113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 92220831 + ... + 96578427.
It is an arithmetic number, because the mean of its divisors is an integer number (34359276761376).
Almost surely, 2411355540131513 is an apocalyptic number.
It is an amenable number.
411355540131513 is a deficient number, since it is larger than the sum of its proper divisors (138392888050503).
411355540131513 is a wasteful number, since it uses less digits than its factorization.
411355540131513 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4430704.
The product of its (nonzero) digits is 270000, while the sum is 42.
Adding to 411355540131513 its reverse (315131045553114), we get a palindrome (726486585684627).
The spelling of 411355540131513 in words is "four hundred eleven trillion, three hundred fifty-five billion, five hundred forty million, one hundred thirty-one thousand, five hundred thirteen".
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