Base | Representation |
---|---|
bin | 10010101101010101011101… |
… | …11110010010010000111011 |
3 | 12101122221212120001002111211 |
4 | 21112222232332102100323 |
5 | 20343014442333340121 |
6 | 223255303232503551 |
7 | 11444163554643361 |
oct | 1126525676222073 |
9 | 171587776032454 |
10 | 41140132324411 |
11 | 121214831a341a |
12 | 47452970aabb7 |
13 | 19c5661975a53 |
14 | a2329b957631 |
15 | 4b5238ae1ce1 |
hex | 256aaef9243b |
41140132324411 has 4 divisors (see below), whose sum is σ = 42143550186024. Its totient is φ = 40136714462800.
The previous prime is 41140132324391. The next prime is 41140132324439. The reversal of 41140132324411 is 11442323104114.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 41140132324411 - 27 = 41140132324283 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (41140132328411) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 501708930745 + ... + 501708930826.
It is an arithmetic number, because the mean of its divisors is an integer number (10535887546506).
Almost surely, 241140132324411 is an apocalyptic number.
41140132324411 is a gapful number since it is divisible by the number (41) formed by its first and last digit.
41140132324411 is a deficient number, since it is larger than the sum of its proper divisors (1003417861613).
41140132324411 is a wasteful number, since it uses less digits than its factorization.
41140132324411 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1003417861612.
The product of its (nonzero) digits is 9216, while the sum is 31.
Adding to 41140132324411 its reverse (11442323104114), we get a palindrome (52582455428525).
The spelling of 41140132324411 in words is "forty-one trillion, one hundred forty billion, one hundred thirty-two million, three hundred twenty-four thousand, four hundred eleven".
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