Base | Representation |
---|---|
bin | 10010101101010111011111… |
… | …11000000110001111001011 |
3 | 12101200001200102222210021002 |
4 | 21112223233320012033023 |
5 | 20343024210113040243 |
6 | 223300003251405215 |
7 | 11444232546264056 |
oct | 1126535770061713 |
9 | 171601612883232 |
10 | 41141221221323 |
11 | 12121991914823 |
12 | 474553b8b380b |
13 | 19c57a6439a52 |
14 | a23362405a9d |
15 | 4b529e4d2eb8 |
hex | 256aefe063cb |
41141221221323 has 4 divisors (see below), whose sum is σ = 41149318298088. Its totient is φ = 41133124144560.
The previous prime is 41141221221307. The next prime is 41141221221389. The reversal of 41141221221323 is 32312212214114.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 41141221221323 - 24 = 41141221221307 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (41141221221823) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4048530761 + ... + 4048540922.
It is an arithmetic number, because the mean of its divisors is an integer number (10287329574522).
Almost surely, 241141221221323 is an apocalyptic number.
41141221221323 is a deficient number, since it is larger than the sum of its proper divisors (8097076765).
41141221221323 is an equidigital number, since it uses as much as digits as its factorization.
41141221221323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8097076764.
The product of its digits is 4608, while the sum is 29.
Adding to 41141221221323 its reverse (32312212214114), we get a palindrome (73453433435437).
The spelling of 41141221221323 in words is "forty-one trillion, one hundred forty-one billion, two hundred twenty-one million, two hundred twenty-one thousand, three hundred twenty-three".
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