Base | Representation |
---|---|
bin | 10010101101011010110101… |
… | …00000001000100010011011 |
3 | 12101200020022010002022101212 |
4 | 21112231122200020202123 |
5 | 20343041341041221103 |
6 | 223300500553333335 |
7 | 11444325100435640 |
oct | 1126553240104233 |
9 | 171606263068355 |
10 | 41143010101403 |
11 | 1212271a673911 |
12 | 474595aa0724b |
13 | 19c59ccc35582 |
14 | a23491c25dc7 |
15 | 4b53565917d8 |
hex | 256b5a80889b |
41143010101403 has 4 divisors (see below), whose sum is σ = 47020582973040. Its totient is φ = 35265437229768.
The previous prime is 41143010101397. The next prime is 41143010101421. The reversal of 41143010101403 is 30410101034114.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 41143010101403 - 212 = 41143010097307 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (41143010101463) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2938786435808 + ... + 2938786435821.
It is an arithmetic number, because the mean of its divisors is an integer number (11755145743260).
Almost surely, 241143010101403 is an apocalyptic number.
41143010101403 is a deficient number, since it is larger than the sum of its proper divisors (5877572871637).
41143010101403 is an equidigital number, since it uses as much as digits as its factorization.
41143010101403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5877572871636.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 41143010101403 its reverse (30410101034114), we get a palindrome (71553111135517).
The spelling of 41143010101403 in words is "forty-one trillion, one hundred forty-three billion, ten million, one hundred one thousand, four hundred three".
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