4114331331401 has 4 divisors (see below), whose sum is σ = 4114577730000. Its totient is φ = 4114084932804.

The previous prime is 4114331331391. The next prime is 4114331331403. The reversal of 4114331331401 is 1041331334114.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4114331331401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4114331331403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 123174251 + ... + 123207648.

It is an arithmetic number, because the mean of its divisors is an integer number (1028644432500).

Almost surely, 2^{4114331331401} is an apocalyptic number.

It is an amenable number.

4114331331401 is a deficient number, since it is larger than the sum of its proper divisors (246398599).

4114331331401 is a wasteful number, since it uses less digits than its factorization.

4114331331401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 246398598.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 4114331331401 its reverse (1041331334114), we get a palindrome (5155662665515).

The spelling of 4114331331401 in words is "four trillion, one hundred fourteen billion, three hundred thirty-one million, three hundred thirty-one thousand, four hundred one".