41143400134433 has 4 divisors (see below), whose sum is σ = 41143693296048. Its totient is φ = 41143106972820.

The previous prime is 41143400134427. The next prime is 41143400134439. The reversal of 41143400134433 is 33443100434114.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (41143400134427) and next prime (41143400134439).

It is a cyclic number.

It is not a de Polignac number, because 41143400134433 - 2²⁶ = 41143333025569 is a prime.

It is a super-2 number, since 2×41143400134433² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 41143400134393 and 41143400134402.

It is not an unprimeable number, because it can be changed into a prime (41143400134439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 146370191 + ... + 146651012.

It is an arithmetic number, because the mean of its divisors is an integer number (10285923324012).

Almost surely, 2^{41143400134433} is an apocalyptic number.

It is an amenable number.

41143400134433 is a deficient number, since it is larger than the sum of its proper divisors (293161615).

41143400134433 is a wasteful number, since it uses less digits than its factorization.

41143400134433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 293161614.

The product of its (nonzero) digits is 82944, while the sum is 35.

Adding to 41143400134433 its reverse (33443100434114), we get a palindrome (74586500568547).

The spelling of 41143400134433 in words is "forty-one trillion, one hundred forty-three billion, four hundred million, one hundred thirty-four thousand, four hundred thirty-three".