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4114748474113 = 17264791440887
BaseRepresentation
bin111011111000001010000…
…111110000001100000001
3112120100212220012011012211
4323320022013300030001
51014404001102132423
612430142300022121
7603165205642324
oct73701207601401
915510786164184
104114748474113
111347067273652
12565570b31941
1323b032cc9124
1410322502c7bb
1572079dc310d
hex3be0a1f0301

4114748474113 has 8 divisors (see below), whose sum is σ = 4358438485632. Its totient is φ = 3871241349696.

The previous prime is 4114748473951. The next prime is 4114748474167. The reversal of 4114748474113 is 3114748474114.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 4114748474113 - 29 = 4114748473601 is a prime.

It is a super-2 number, since 2×41147484741132 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4114748474513) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 45675445 + ... + 45765442.

It is an arithmetic number, because the mean of its divisors is an integer number (544804810704).

Almost surely, 24114748474113 is an apocalyptic number.

It is an amenable number.

4114748474113 is a deficient number, since it is larger than the sum of its proper divisors (243690011519).

4114748474113 is a wasteful number, since it uses less digits than its factorization.

4114748474113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 91443551.

The product of its digits is 1204224, while the sum is 49.

Subtracting from 4114748474113 its reverse (3114748474114), we obtain a palindrome (999999999999).

The spelling of 4114748474113 in words is "four trillion, one hundred fourteen billion, seven hundred forty-eight million, four hundred seventy-four thousand, one hundred thirteen".

Divisors: 1 17 2647 44999 91440887 1554495079 242044027889 4114748474113