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4115132241603 = 31371710747201
BaseRepresentation
bin111011111000100000111…
…111101101011011000011
3112120101212122022120020120
4323320200333231123003
51014410242323212403
612430244325311323
7603210545626065
oct73704077553303
915511778276216
104115132241603
111347243961869
12565659565543
1323b094676096
1410325dda9735
157209d92be53
hex3be20fed6c3

4115132241603 has 4 divisors (see below), whose sum is σ = 5486842988808. Its totient is φ = 2743421494400.

The previous prime is 4115132241587. The next prime is 4115132241617. The reversal of 4115132241603 is 3061422315114.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4115132241603 - 24 = 4115132241587 is a prime.

It is not an unprimeable number, because it can be changed into a prime (4115132241673) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 685855373598 + ... + 685855373603.

It is an arithmetic number, because the mean of its divisors is an integer number (1371710747202).

Almost surely, 24115132241603 is an apocalyptic number.

4115132241603 is a deficient number, since it is larger than the sum of its proper divisors (1371710747205).

4115132241603 is a wasteful number, since it uses less digits than its factorization.

4115132241603 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1371710747204.

The product of its (nonzero) digits is 17280, while the sum is 33.

Adding to 4115132241603 its reverse (3061422315114), we get a palindrome (7176554556717).

The spelling of 4115132241603 in words is "four trillion, one hundred fifteen billion, one hundred thirty-two million, two hundred forty-one thousand, six hundred three".

Divisors: 1 3 1371710747201 4115132241603