Base | Representation |
---|---|
bin | 111011111000101101011… |
… | …101010010110100100011 |
3 | 112120102102012202000202120 |
4 | 323320231131102310203 |
5 | 1014411204334323210 |
6 | 12430321154515323 |
7 | 603215665040340 |
oct | 73705535226443 |
9 | 15512365660676 |
10 | 4115341323555 |
11 | 1347340988170 |
12 | 5656b7595b43 |
13 | 23b0c8a90107 |
14 | 10327da737c7 |
15 | 720b1e7c270 |
hex | 3be2d752d23 |
4115341323555 has 128 divisors (see below), whose sum is σ = 8385879269376. Its totient is φ = 1673870592000.
The previous prime is 4115341323517. The next prime is 4115341323593. The reversal of 4115341323555 is 5553231435114.
It is an interprime number because it is at equal distance from previous prime (4115341323517) and next prime (4115341323593).
It is not a de Polignac number, because 4115341323555 - 224 = 4115324546339 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 10056955 + ... + 10458155.
It is an arithmetic number, because the mean of its divisors is an integer number (65514681792).
Almost surely, 24115341323555 is an apocalyptic number.
4115341323555 is an abundant number, since it is smaller than the sum of its proper divisors (4270537945821).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
4115341323555 is a wasteful number, since it uses less digits than its factorization.
4115341323555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 401417.
The product of its digits is 540000, while the sum is 42.
Adding to 4115341323555 its reverse (5553231435114), we get a palindrome (9668572758669).
The spelling of 4115341323555 in words is "four trillion, one hundred fifteen billion, three hundred forty-one million, three hundred twenty-three thousand, five hundred fifty-five".
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