Base | Representation |
---|---|
bin | 100110010101000000… |
… | …011110100101010001 |
3 | 10221020010201010110222 |
4 | 212111000132211101 |
5 | 1133241041323423 |
6 | 30523422402425 |
7 | 2654564430563 |
oct | 462500364521 |
9 | 127203633428 |
10 | 41154636113 |
11 | 164a97a0268 |
12 | 7b86730415 |
13 | 3b5b3528b6 |
14 | 1dc5a8d333 |
15 | 110d0613c8 |
hex | 99501e951 |
41154636113 has 4 divisors (see below), whose sum is σ = 41185791588. Its totient is φ = 41123480640.
The previous prime is 41154636071. The next prime is 41154636151. The reversal of 41154636113 is 31163645114.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 17729721409 + 23424914704 = 133153^2 + 153052^2 .
It is a cyclic number.
It is not a de Polignac number, because 41154636113 - 212 = 41154632017 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (41154630113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15575756 + ... + 15578397.
It is an arithmetic number, because the mean of its divisors is an integer number (10296447897).
Almost surely, 241154636113 is an apocalyptic number.
It is an amenable number.
41154636113 is a deficient number, since it is larger than the sum of its proper divisors (31155475).
41154636113 is a wasteful number, since it uses less digits than its factorization.
41154636113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 31155474.
The product of its digits is 25920, while the sum is 35.
Subtracting from 41154636113 its reverse (31163645114), we obtain a palindrome (9990990999).
The spelling of 41154636113 in words is "forty-one billion, one hundred fifty-four million, six hundred thirty-six thousand, one hundred thirteen".
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