Base | Representation |
---|---|
bin | 111011111011001100011… |
… | …010100100011011000001 |
3 | 112120200022001220201001111 |
4 | 323323030122210123001 |
5 | 1014432140043432221 |
6 | 12431441543003321 |
7 | 603342040021213 |
oct | 73731432443301 |
9 | 15520261821044 |
10 | 4118008186561 |
11 | 134848a2a0885 |
12 | 566120739541 |
13 | 23b432443a69 |
14 | 103453d1c5b3 |
15 | 721bb168be1 |
hex | 3becc6a46c1 |
4118008186561 has 4 divisors (see below), whose sum is σ = 4118013486000. Its totient is φ = 4118002887124.
The previous prime is 4118008186553. The next prime is 4118008186571. The reversal of 4118008186561 is 1656818008114.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 4118008186561 - 23 = 4118008186553 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4118008186571) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1230871 + ... + 3122668.
It is an arithmetic number, because the mean of its divisors is an integer number (1029503371500).
Almost surely, 24118008186561 is an apocalyptic number.
It is an amenable number.
4118008186561 is a deficient number, since it is larger than the sum of its proper divisors (5299439).
4118008186561 is an equidigital number, since it uses as much as digits as its factorization.
4118008186561 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5299438.
The product of its (nonzero) digits is 368640, while the sum is 49.
The spelling of 4118008186561 in words is "four trillion, one hundred eighteen billion, eight million, one hundred eighty-six thousand, five hundred sixty-one".
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