Base | Representation |
---|---|
bin | 10010101111001000110010… |
… | …10010010100011011100001 |
3 | 12101212212200101121110011202 |
4 | 21113210121102110123201 |
5 | 20400023242122100301 |
6 | 223343543003050545 |
7 | 11451515045166662 |
oct | 1127443122243341 |
9 | 171785611543152 |
10 | 41202045503201 |
11 | 12145764607a80 |
12 | 4755295810a55 |
13 | 19cb44a89c19b |
14 | a26292545369 |
15 | 4b6b5e2a766b |
hex | 2579194946e1 |
41202045503201 has 4 divisors (see below), whose sum is σ = 44947686003504. Its totient is φ = 37456405002900.
The previous prime is 41202045503197. The next prime is 41202045503207. The reversal of 41202045503201 is 10230554020214.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 41202045503201 - 22 = 41202045503197 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (41202045503207) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1872820250135 + ... + 1872820250156.
It is an arithmetic number, because the mean of its divisors is an integer number (11236921500876).
Almost surely, 241202045503201 is an apocalyptic number.
It is an amenable number.
41202045503201 is a deficient number, since it is larger than the sum of its proper divisors (3745640500303).
41202045503201 is a wasteful number, since it uses less digits than its factorization.
41202045503201 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3745640500302.
The product of its (nonzero) digits is 9600, while the sum is 29.
Adding to 41202045503201 its reverse (10230554020214), we get a palindrome (51432599523415).
The spelling of 41202045503201 in words is "forty-one trillion, two hundred two billion, forty-five million, five hundred three thousand, two hundred one".
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