Base | Representation |
---|---|
bin | 101110110101111111000101… |
… | …0101000011101110011011011 |
3 | 2000000220122021222121211012011 |
4 | 1131223332022220131303123 |
5 | 413001330421412433103 |
6 | 4020200322523130351 |
7 | 152534623434200425 |
oct | 13553761250356333 |
9 | 2000818258554164 |
10 | 412040013405403 |
11 | 10a31a208785189 |
12 | 3a2681469739b7 |
13 | 148bb28ba04786 |
14 | 73a6bb34c3815 |
15 | 329818dcd2d6d |
hex | 176bf8aa1dcdb |
412040013405403 has 4 divisors (see below), whose sum is σ = 412040303531128. Its totient is φ = 412039723279680.
The previous prime is 412040013405389. The next prime is 412040013405457. The reversal of 412040013405403 is 304504310040214.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-412040013405403 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (412040013405463) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 142922013 + ... + 145776478.
It is an arithmetic number, because the mean of its divisors is an integer number (103010075882782).
Almost surely, 2412040013405403 is an apocalyptic number.
412040013405403 is a deficient number, since it is larger than the sum of its proper divisors (290125725).
412040013405403 is a wasteful number, since it uses less digits than its factorization.
412040013405403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 290125724.
The product of its (nonzero) digits is 23040, while the sum is 31.
Adding to 412040013405403 its reverse (304504310040214), we get a palindrome (716544323445617).
The spelling of 412040013405403 in words is "four hundred twelve trillion, forty billion, thirteen million, four hundred five thousand, four hundred three".
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