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412040013405403 = 1427233288698491
BaseRepresentation
bin101110110101111111000101…
…0101000011101110011011011
32000000220122021222121211012011
41131223332022220131303123
5413001330421412433103
64020200322523130351
7152534623434200425
oct13553761250356333
92000818258554164
10412040013405403
1110a31a208785189
123a2681469739b7
13148bb28ba04786
1473a6bb34c3815
15329818dcd2d6d
hex176bf8aa1dcdb

412040013405403 has 4 divisors (see below), whose sum is σ = 412040303531128. Its totient is φ = 412039723279680.

The previous prime is 412040013405389. The next prime is 412040013405457. The reversal of 412040013405403 is 304504310040214.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-412040013405403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (412040013405463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 142922013 + ... + 145776478.

It is an arithmetic number, because the mean of its divisors is an integer number (103010075882782).

Almost surely, 2412040013405403 is an apocalyptic number.

412040013405403 is a deficient number, since it is larger than the sum of its proper divisors (290125725).

412040013405403 is a wasteful number, since it uses less digits than its factorization.

412040013405403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 290125724.

The product of its (nonzero) digits is 23040, while the sum is 31.

Adding to 412040013405403 its reverse (304504310040214), we get a palindrome (716544323445617).

The spelling of 412040013405403 in words is "four hundred twelve trillion, forty billion, thirteen million, four hundred five thousand, four hundred three".

Divisors: 1 1427233 288698491 412040013405403