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412412003113 = 1137492000283
BaseRepresentation
bin1100000000001011010…
…10111100001100101001
31110102111200221110100211
412000011222330030221
523224104433044423
6513243124301121
741536645121005
oct6000552741451
91412450843324
10412412003113
111499a2908010
1267b17b417a1
132cb75c57996
1415d647cb705
15aadb3ee10d
hex6005abc329

412412003113 has 4 divisors (see below), whose sum is σ = 449904003408. Its totient is φ = 374920002820.

The previous prime is 412412003099. The next prime is 412412003141. The reversal of 412412003113 is 311300214214.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a de Polignac number, because none of the positive numbers 2k-412412003113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (412412003813) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18746000131 + ... + 18746000152.

It is an arithmetic number, because the mean of its divisors is an integer number (112476000852).

Almost surely, 2412412003113 is an apocalyptic number.

It is an amenable number.

412412003113 is a deficient number, since it is larger than the sum of its proper divisors (37492000295).

412412003113 is a wasteful number, since it uses less digits than its factorization.

412412003113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37492000294.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 412412003113 its reverse (311300214214), we get a palindrome (723712217327).

The spelling of 412412003113 in words is "four hundred twelve billion, four hundred twelve million, three thousand, one hundred thirteen".

Divisors: 1 11 37492000283 412412003113