Base | Representation |
---|---|
bin | 111100000000111000101… |
… | …110100011000011001001 |
3 | 112121021002000222210012202 |
4 | 330000320232203003021 |
5 | 1020032144301033231 |
6 | 12434332243245545 |
7 | 603646355260526 |
oct | 74007056430311 |
9 | 15537060883182 |
10 | 4124120330441 |
11 | 1350036457a61 |
12 | 5673476798b5 |
13 | 23bb97815947 |
14 | 1038739a014d |
15 | 72427a545cb |
hex | 3c038ba30c9 |
4124120330441 has 4 divisors (see below), whose sum is σ = 4124168077584. Its totient is φ = 4124072583300.
The previous prime is 4124120330437. The next prime is 4124120330467. The reversal of 4124120330441 is 1440330214214.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 4124120330441 - 22 = 4124120330437 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4124120390441) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23743775 + ... + 23916836.
It is an arithmetic number, because the mean of its divisors is an integer number (1031042019396).
Almost surely, 24124120330441 is an apocalyptic number.
It is an amenable number.
4124120330441 is a deficient number, since it is larger than the sum of its proper divisors (47747143).
4124120330441 is an equidigital number, since it uses as much as digits as its factorization.
4124120330441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47747142.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 4124120330441 its reverse (1440330214214), we get a palindrome (5564450544655).
The spelling of 4124120330441 in words is "four trillion, one hundred twenty-four billion, one hundred twenty million, three hundred thirty thousand, four hundred forty-one".
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