4124214113 has 4 divisors (see below), whose sum is σ = 4124369940. Its totient is φ = 4124058288.

The previous prime is 4124214097. The next prime is 4124214121. The reversal of 4124214113 is 3114124214.

4124214113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 982947904 + 3141266209 = 31352^2 + 56047^2 .

It is a cyclic number.

It is not a de Polignac number, because 4124214113 - 2⁴ = 4124214097 is a prime.

It is a super-3 number, since 3×4124214113³ (a number of 30 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4124214163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27218 + ... + 94811.

It is an arithmetic number, because the mean of its divisors is an integer number (1031092485).

Almost surely, 2^4124214113 is an apocalyptic number.

It is an amenable number.

4124214113 is a deficient number, since it is larger than the sum of its proper divisors (155827).

4124214113 is a wasteful number, since it uses less digits than its factorization.

4124214113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 155826.

The product of its digits is 768, while the sum is 23.

The square root of 4124214113 is about 64220.0444798974. The cubic root of 4124214113 is about 1603.6653096592.

Adding to 4124214113 its reverse (3114124214), we get a palindrome (7238338327).

It can be divided in two parts, 41242 and 14113, that added together give a palindrome (55355).

The spelling of 4124214113 in words is "four billion, one hundred twenty-four million, two hundred fourteen thousand, one hundred thirteen".