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41243025515113 = 192170685553427
BaseRepresentation
bin10010110000010101000111…
…11000101010001001101001
312102000210110100201202021201
421120022203320222021221
520401211204012440423
6223414441231004201
711454465422432242
oct1130124370521151
9172023410652251
1041243025515113
1112161083777514
124761211969661
131a0227b9b0a46
14a2825cd39cc9
154b7c5bd232ad
hex2582a3e2a269

41243025515113 has 4 divisors (see below), whose sum is σ = 43413711068560. Its totient is φ = 39072339961668.

The previous prime is 41243025515077. The next prime is 41243025515143. The reversal of 41243025515113 is 31151552034214.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 41243025515113 - 29 = 41243025514601 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (41243025515143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1085342776695 + ... + 1085342776732.

It is an arithmetic number, because the mean of its divisors is an integer number (10853427767140).

Almost surely, 241243025515113 is an apocalyptic number.

It is an amenable number.

41243025515113 is a deficient number, since it is larger than the sum of its proper divisors (2170685553447).

41243025515113 is a wasteful number, since it uses less digits than its factorization.

41243025515113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2170685553446.

The product of its (nonzero) digits is 72000, while the sum is 37.

Adding to 41243025515113 its reverse (31151552034214), we get a palindrome (72394577549327).

The spelling of 41243025515113 in words is "forty-one trillion, two hundred forty-three billion, twenty-five million, five hundred fifteen thousand, one hundred thirteen".

Divisors: 1 19 2170685553427 41243025515113