412551213530553 has 6 divisors (see below), whose sum is σ = 595907308433034. Its totient is φ = 275034142353696.

The previous prime is 412551213530483. The next prime is 412551213530557. The reversal of 412551213530553 is 355035312155214.

412551213530553 is a `hidden beast` number, since 4 + 1 + 2 + 5 + 51 + 2 + 13 + 5 + 30 + 553 = 666.

It can be written as a sum of positive squares in only one way, i.e., 366445375274169 + 46105838256384 = 19142763^2 + 6790128^2 .

It is not a de Polignac number, because 412551213530553 - 2¹⁰ = 412551213529529 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 412551213530499 and 412551213530508.

It is not an unprimeable number, because it can be changed into a prime (412551213530557) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 22919511862800 + ... + 22919511862817.

It is an arithmetic number, because the mean of its divisors is an integer number (99317884738839).

Almost surely, 2^{412551213530553} is an apocalyptic number.

It is an amenable number.

412551213530553 is a deficient number, since it is larger than the sum of its proper divisors (183356094902481).

412551213530553 is a wasteful number, since it uses less digits than its factorization.

412551213530553 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 45839023725623 (or 45839023725620 counting only the distinct ones).

The product of its (nonzero) digits is 1350000, while the sum is 45.

Adding to 412551213530553 its reverse (355035312155214), we get a palindrome (767586525685767).

The spelling of 412551213530553 in words is "four hundred twelve trillion, five hundred fifty-one billion, two hundred thirteen million, five hundred thirty thousand, five hundred fifty-three".